I just wanted to try this because of a thought I had about dimensionality.

#include <stdio.h> #include <math.h> /* Doing Pi Add sqrt(1-x^2) from 0 to 1 divide by steps */ int main(int argc, char *argv[]) { double s,stepsize,MyPi=0.0,d,fsteps=100000000.0; int i,steps=100000000;stepsize=1/(fsteps); for (i=1;i<steps;i++) { s = sqrt(1-(stepsize*i)*(stepsize*i)); MyPi=MyPi+s; } d=MyPi/fsteps; printf (" it is %f %f\n",4*d,M_PI); return 0; }

It is compiled with "gcc program.c -o program -lm" and run as "./program" which yields 3.141593

That seems rather odd to me somehow that on the range, 0 to 1, ∑(1-x²)^{½}Δx=PI? It could just be the day as I sometimes have transient confusion when I am changing perspective on dimensional space.

ALSO:

∫(1-x²)^{½}δx

I could use a trigonometric substitution and just do the work, but I wanted to play with mirror inversion of formulas in several dimensions, branching to infinity relationships and how this relates to other equations that have PI as a limit or factor.

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